Question

Determine the smallest integer value of x in the solution of the following inequality.

-3x+10≤5

Answer 1

Answer: The smallest integer value of x in the solution is 1.

Explanation:

The given inequality:
`-3x+10\leq5`

To solve the inequality, we first subtract 10 from both sides

`-3x+10-10\leq5-10\\\\\Rightarrow\ -3x\leq-5`

Multiply negative sign on both sides ,we get

`3x\geq5`

Divide both sides by 3, we get

`x\geq(5)/(3)`

i.e.
`x\geq 1.6666666667\\`

`x\geq1`

Hence, the smallest integer value of x in the solution is 1.