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3 votes
3(2^2x+3)-5(2^x+2)-156=0

User Scrimothy
by
8.7k points

1 Answer

1 vote

Answer:
x=3.0206

Explanation:

Given


3(2^(2x)+3)-5(2^x+2)-156=0

Replace
2^x by
y

We can write


\Rightarrow 3(y^2+3)-5(y+2)-156=0\\\Rightarrow 3y^2+9-5y-10-156=0\\\Rightarrow 3y^2-5y-157=0\\\\\Rightarrow y=(5\pm √(25-4(3)(-157)))/(2* 3)\\\\\Rightarrow y=(5+43.69)/(6)\\\\\Rightarrow y=8.115\\\Rightarrow 2^x=8.115\\\therefore \quad x=3.0206

User GuLearn
by
8.5k points

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