Question

Who could help me please and thank you

Only answer if you know how to do the equation

Answer 1

Let's find the slope of the line passing through it :

`\boxed{ slope = (y_2-y_1)/( x_2- x_1) }`

• 
  `( -5 - ( - 6))/(0 - ( - 5))`

• 
  `(1)/(5)`

Now, we know, equation of a line is :

`\longrightarrow y = mx + b`

where,

• m represents the slope

Therefore,

`\longrightarrow \: y = (1)/(5) x + b`

let's put the value of x and y from the first coordinates .

• 
  `y = (x)/(5) + b`

• 
  `- 5 = (0)/(5) + b`

• 
  `b = - 5`

Hence, we got the equation of line as :

• 
  `y = (x)/(5) - 5`

or

• 
  `5y = x - 25`

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