Question

Factor 4x^2 + 1x – 13

Answer 1

`(x - (√(209) - 1)/(8) )(x - (-1 - √(209) )/(8) )`

Explanation:

FACTS TO KNOW BEFORE SOLVING :-

Quadratic Formula :-

Lets say , there's an equation ax² + bx + c.

`=> x = (-b + √(b^2 - 4ac) )/(2a) \: or \: (-b - √(b^2 - 4ac) )/(2a)`

SOLUTION :-

According to the question ,

• a (Coefficient of x²) = 4

• b (Coefficient of x) = 1

• c (constant) = -13

By using quadratic formula ,

`x = (-1 + √(1^2 - 4 * 4 * (-13)) )/(2 * 4) \: or \: (-1 - √(1^2 - 4 * 4 * (-13)) )/(2 * 4)`

`=> x = (-1 + √(209) )/(8) \: or \: (-1 - √(209) )/(8)`

`=> (x - (√(209) - 1)/(8) ) \: and \: (x - (-1 - √(209) )/(8) )` are the factors of 4x² + x - 13.