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Between 06 00 and 10 00,the same day, the volume of water in a reservoir decreased from 24 000 L to 18 000 L. What was the average rate of decrease in volume of water, giving your answer in L/h ?

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Answer:

Explanation:

Given,

Time taken (t) = 10 - 6 = 4hrs

Water decreased (V) = 24000l - 18000l = 6000l

Now,

average rate of decrase (Avg) = V/t = 6000l/4 =1500 L/h

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