Answer:
b. (2,0)
Explanation:
To find which ordered pair is a solution, we have to replace then into the equation, and the result has to be an identity, that is, 0 = 0.
Equation:
![y = -5x + 10](https://img.qammunity.org/2022/formulas/mathematics/college/l3gfep2zvvayjysyvxkvlkxtnn464zn5yb.png)
Option a:
, so
![x = -15, y = 5](https://img.qammunity.org/2022/formulas/mathematics/college/bgca5g962yst4xzpw1pv15pxq2vg4dzfgn.png)
![y = -5x + 10](https://img.qammunity.org/2022/formulas/mathematics/college/l3gfep2zvvayjysyvxkvlkxtnn464zn5yb.png)
![5 = -5(-15) + 10](https://img.qammunity.org/2022/formulas/mathematics/college/xuq9o87w5ane1dz5tnyqx9k568fh5kxvpj.png)
![5 = 75 + 10](https://img.qammunity.org/2022/formulas/mathematics/college/o6iqfxzwo9rpjnj8fy9pu8szen49r9ydzz.png)
![5 = 85](https://img.qammunity.org/2022/formulas/mathematics/college/tj6u5cjzrp07gmr7avtru8x0ms3r72ct7o.png)
Not an identity, so this ordered pair is not a solution.
Option b:
, so
![x = 2, y = 0](https://img.qammunity.org/2022/formulas/mathematics/college/tdgvti2ouest1ehkuo06aoltddwwksykwa.png)
![y = -5x + 10](https://img.qammunity.org/2022/formulas/mathematics/college/l3gfep2zvvayjysyvxkvlkxtnn464zn5yb.png)
![0 = -5(2) + 10](https://img.qammunity.org/2022/formulas/mathematics/college/1w09expz0b2isfju0tqcj07jdfcppe8cpj.png)
![0 = -10 + 10](https://img.qammunity.org/2022/formulas/mathematics/college/q1v7mkm9yk73dapch6ukxidar7ao2jyslz.png)
![0 = 0](https://img.qammunity.org/2022/formulas/mathematics/high-school/3t6cwj462ecwukpzqk8s37s1qf76xgq4yk.png)
Identity, and thus, the correct answer is given by option b.