Question

A positive charge of 8.0 × 10-4 C is in an electric field that exerts a force of 3.5 × 10-4 N on it. What is the strength of the electric field?

Answer 1

E = 0.437 N/C

Step-by-step explanation:

Given that,

Charge,
`q=8* 10^(-4)\ C`

Electric force,
`F=3.5* 10^(-4)\ N`

Let the strength of the electric field is E. We know that, the electric force is given by :

F = qE

Where

E is the electric field strength

`E=(F)/(q)\\\\E=(3.5* 10^(-4))/(8* 10^(-4))\\E=0.437\ N/C`

So, the strength of the electric field is equal to 0.437 N/C.