Question

A marble block of mass 2 kg lying on ice when given a velocity of 6 m/s is stopped by a friction in 10s then what is the coefficient of friction?​

Answer 1

`\mu=0.06`

Step-by-step explanation:

Given that,

Mass of a block, m = 2 kg

Velocity of the block, v = 6 m/s

It stopped in 10 s

We need to find the coefficient of friction.

The frictional force is balanced by the opposing force such that,

`\mu mg=ma\\\\\mu=(a)/(g)`

Where

a is acceleration, a = 6/10 = 0.6 m/s

So,

`\mu=(0.6)/(10)\\\\\mu=0.06`

So, the coefficient of friction is equal to 0.06.