Question

Determine the number of molecules of C2CI4 contained in 73.1g of C2CI4

Answer 1

2.35x10²³ molecules of C2Cl4 are present

Step-by-step explanation:

To solve this question we must convert, as first, the mass of C2Cl4 to moles using its molar mass (C2Cl4 = 165.83g/mol). Then, using Avogadro's number we can find the number of molecules:

Moles C2Cl4:

73.1g * (1mol / 165.83g) = 0.441 moles C2Cl4

Molecules:

0.441 moles C2Cl4 * (6.022x10²³molecules / 1mol) =

2.35x10²³ molecules of C2Cl4 are present