Answer:
5units
Explanation:
d=√(x2-x1)^2+(y2-y1)^2
d=√(6-2)^2+(8-5)^2
d=√4^2+3^2
d=√16+9
d=√25
d=5
5
formula for distance between two lines √(x2-x1)²+(y2-y1)²
√(6-2)²+(8-5)²
√4²+3²
√16+9
√25
=5
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