Question

3. Suppose you take a pendulum with length L and mass m having a period T to a

planet where the value of g is 176 of the value on Earth. What would be the period
of the pendulum on the planet? *
T/6
OT
O 1.6T
2.4 T
4.6 T
help fast

Answer 1

(C)

Step-by-step explanation:

`t = 2\pi \sqrt{ (l)/(g) }`

If g is only 1/6 on another planet, then

`t = 2\pi \sqrt{ (l)/( (g)/(6) ) } = 2\pi \sqrt{ (6l)/(g) }`

`= √(6) \: (2\pi \sqrt{ (l)/(g) } ) = 2.4 * t(on \: earth)`