Question

-x+2y=8

How do I put this into slope-intercept form???

If you can please show your work!

Answer 1

`\mathrm{slope\:intercept\:form:\:y = ( 1 )/( 2 ) x+4}`

Explanation:

To change the equation into slope-intercept form, we write it in the form y=mx+b

So this means that we have to solve for "y" in the equation "-x + 2y = 8"

−x + 2y = 8

Step 1: Add x to both sides

2y = 8 + x

Step 2: Now the equation is in standard form

2y = x + 8

Step 3: Divide both sides by 2

`\mathrm{( 2y )/( 2 ) = ( x+8 )/( 2 )}`

Step 4: Dividing by 2 undoes the multiplication by 2

`\mathrm{y = ( 1 )/( 2 ) x+4}`