Question

Solve M2 + 6m = -8 using quadratic formula??​

Answer 1

m=-4,-2

Explanation:

Hi there!

What we need to know:

• The quadratic formula:
  `x=(-b\pm√(b^2-4ac) )/(2a)` where the equation is given in standard form
• Standard form quadratic equation:
  `y=ax^2+bx+c` (with y=0)

1) Rearrange the given equation into standard form

This will help us determine the a, b and c values.

`m^2+6m=-8`

Add 8 to both sides

`m^2+6m+8=0`

Now, we can see that a=1, b=6 and c=8.

2) Plug a, b and c into the quadratic formula

`m=(-b\pm√(b^2-4ac) )/(2a)\\m=(-6\pm√(6^2-4(1)(8)) )/(2(1))\\m=(-6\pm√(4) )/(2)\\m=(-6\pm2 )/(2)\\m=-3\pm1 \\m=-4,-2`

I hope this helps!