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Between 02 30 and 05 30,the same day,the volume of water in a reservoir increased from 6000 L to 18 000 L.What was the average rate of increase in volume of water,giving your answer in L/h?

User Oldskool
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Answer:

4,000 L/h

Explanation:

First we'll find the amount of the change.

18,000 - 6,000 = 12,000 L

The time of the volume change was 3 hours: 0230 - 0530

Since we're looking for liters per hour, we will divide the liters (12,000) by the hours (3)

12,000/3 = 4,000 L/h

User Binarycreations
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