Question

Determine the spec gravity of 500 mL alcohol if the density is 0.79g/ml

Answer 1

S.G = 0.79.

Step-by-step explanation:

Hello there!

In this case, according to the given information in the problem, it turns out possible for us to calculate the specific gravity of this alcohol by simply dividing its density, 0.79 g/mL by that of the water, 1 g/mL just as a reference for us to work with:

`S.G=(\rho _(alc))/(\rho _w)`

Thus, we plug in the densities to obtain:

`S.G=(0.79g/mL)/(1g/mL)\\\\S.G=0.79`

Which is dimensionless as g/mL is cancelled out due to its presence on both top and bottom of the previous formula.

Regards!