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What is the range of y= sec-'(x)? PreCal, send help please!!

What is the range of y= sec-'(x)? PreCal, send help please!!-example-1
User PullJosh
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1 Answer

1 vote

Given:

The function is:


y=\sec^(-1)(x)

To find:

The range of the given function.

Solution:

We have,


y=\sec^(-1)(x)

The range of secant inverse function is:


Range=\0\leq y\leq \pi , y\\eq (\pi)/(2)\

The range of the given function in interval notation is:


Range=\left[0,(\pi)/(2)\right)\text{ and }\left( (\pi)/(2), \pi\right ]

Therefore, the correct option is C.

User Josiane
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3.6k points