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If the index of refraction for a certain glass is 1.5, and the angle of refraction is 15 degrees for a ray of light

traveling from air (index of 1) what is the angle of incidence? (in coming beam)
Round your answer to the nearest tenth of a digit. The answer is in degrees so don't worry about the units

1 Answer

6 votes

Answer:


\theta_i = 23^o

Step-by-step explanation:

The refractive index of a medium is given by the following formula:


\eta = (Sin\theta_i)/(Sin\theta_r)

where,

η = refractive index = 1.5


\theta_i = angle of incidence = ?


\theta_r = angle of refraction = 15°

Therefore,


1.5 = (Sin\theta_i)/(Sin15^o)\\\\Sin\theta_i=(1.5)Sin15^o\\\\\theta_i = Sin^(-1)(0.388)\\\\


\theta_i = 23^o

User Boris Yakubchik
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