Question

In ΔNOP, the measure of ∠P=90°, PO = 48, NP = 55, and ON = 73. What is the value of the sine of ∠N to the nearest hundredth?

Answer 1

`\sin(N) = 0.66`

Explanation:

Given

`\angle P = 90^o`

`PO = 48; NP = 55; ON = 73`

Required

`\sin(N)`

The given parameters is illustrated with the attached image.

From the attached, we have:

`\sin(N) = (Opposite)/(Hypotenuse)`

`\sin(N) = (PO)/(ON)`

`\sin(N) = (48)/(73)`

`\sin(N) = 0.66` -- approximated