Question

what is the magnitude of an electric field (in 106 n/c) that balances the weight of a plastic sphere of mass 2.1 g that has been charged to 3.0 nc

Answer 1

`E=6.86* 10^6\ N/C`

Step-by-step explanation:

Given that,

Mass of the sphere, m = 2.1 g = 0.0021 kg

Charge, q = 3 nC

We need to find the magnitude of the electric field that balanced the weight of sphere. Let it is E. So,

qE = mg

`E=(mg)/(q)`

Put all the values,

`E=(0.0021* 9.8)/(3* 10^(-9))\\\\E=6.86* 10^6\ N/C`

So, the magnitude of the elecric field is
`6.86* 10^6\ N/C`.