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Assume a substance X has a body centered cubic lattice. The edge length is 379.0 pm. The atomic mass of X is 195.0 amu What is the density of Xin g/cc

User Xneg
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1 Answer

4 votes

Answer:


\rho=12g/cm^3

Step-by-step explanation:

From the question we are told that:

Length
l=379.0pm=>379*10^(-10)cm

Atomic mass of X
M= 195.0 amu=>gmol^(-1)

Where


Avogadro\ constant = 6.023 * 10^(23) mol-1

Let

The Number of units in BCC unit cell
n= 2

Generally the equation for Density is mathematically given by


\rho= (M x n)/(l^3*Avogadro constant)


\rho=(197 x 2)/((379*10^(-10))^3*6.023 x 10^(23))


\rho=12g/cm^3

Therefore he density of Xin g/cc


\rho=12g/cm^3

User Rajesh Pantula
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