Question

If g of chlorine gas occupies a volume of mL at a particular temperature and pressure, what volume will g of chlorine gas occupy under the same conditions

Answer 1

The complete question is as follows: If 1.04 g of chlorine gas occupies a volume of 872 mL at a particular temperature and pressure, what volume will 2.08 g of chlorine gas occupy under the same conditions ?

Answer: A volume of 1744 L will 2.08 g of chlorine gas occupy under the same conditions.

Step-by-step explanation:

Given:
`Mass_1` = 1.04 g,
`V_(1)` = 872 mL

`Mass_2` = 2.08 g,
`V_(2)` = ?

As molar mass of chlorine is 35.5 g/mol.

Number of moles is the mass of a substance divided by its molar mass.

Hence, moles of chlorine present in 1.04 g chlorine gas is calculated as follows.

`Moles = (mass)/(molar mass)\\= (1.04 g)/(35.5 g/mol)\\= 0.029 mol`

Also, moles of chlorine present in 2.08 g chlorine gas is calculated as follows.

`Moles = (2.08 g)/(35.5 g/mol)\\= 0.058 mol`

Formula used to calculate the volume occupied by 2.08 g of chlorine gas is as follows.

`(V_(1))/(n_(1)) = (V_(2))/(n_(2))`

Substitute the values into above formula as follows.

`(V_(1))/(n_(1)) = (V_(2))/(n_(2))\\(872 L)/(0.029 mol) = (V_(2))/(0.058 mol)\\V_(2) = 1744 L`

Thus, we can conclude that a volume of 1744 L will 2.08 g of chlorine gas occupy under the same conditions.