Answer:
2.4 m/s
Step-by-step explanation:
Applying,
The law of conservation of momentum
Total momentum before collision = Total momentum after collision
mu+m'u' = mv+m'v'.................... Equation 1
Where m = mass of the moving puck, m' = mass of the stationary puck, u = initial velocity of the moving puck, u' = initial velocity of the stationary puck, v = final velocity of the moving puck, v' = final velocity of the stationary puck.
make v' the subject of the equation
v' = (mu+m'u'-mv)/m'................ Equation 2
From the question,
Given; m = 3 kg, m' = 2 kg, u = 2 m/s, u' = 0 m/s (stationary), v = 0.4 m/s
Substitute these values into equation 2
v' = [(3×2)+(2×0)-(3×0.4)]/2
v' = (6-1.2)/2
v' = 4.8/2
v' = 2.4 m/s