Question

A 2.00 L flask is filled with propane gas (C3H8) at a pressure of 1.10 atm and a temperature of 258 K. What is the mass of propane in the flask?

Answer 1

m = 4.58 g.

Step-by-step explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to realize this problem is solved via the ideal gas equation:

`PV=nRT`

As we can calculate the moles of propane given the pressure, temperature and volume as shown below:

`n=(PV)/(RT) \\\\n=(1.10atm*2.00L)/(0.08206(atm*L)/(mol*K)*258K) \\\\n=0.104mol`

Finally, since the molar mass of propane is 44.1 g/mol, we calculate the mass by following the shown below mole-mass conversion factor:

`m=0.104mol*(44.1g)/(1mol)\\\\m= 4.58g`

Regards!