Question

What is the pressure of a 0.108 mol sample of helium gas at a temperature of 293 K if its volume is 0.505 L?

Answer 1

P = 5.14 atm

Step-by-step explanation:

Given that,

Pressure of the gas, P = 0.108 mol

Temperature, T = 293 K

Volume, V = 0.505 L

We need to find the pressure of the gas. We know that, according to ideal gas equation,

PV = nRT

Where

P is pressure and R is gas constant

`P=(nRT)/(V)\\\\P=(0.108 * 0.0821* 293)/(0.505)\\\\P=5.14\ atm`

So, the pressure of the gas is equal to 5.14 atm.