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Hydrogen gas and nitrogen gas react to form ammonia gas. What volume of ammonia would be produced by this reaction if 5.53 mL of hydrogen were consumed

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Answer:

5.53 mL of hydrogen will produce 3.6867 mL of Ammonia

Step-by-step explanation:

The complete balance equation for the given reaction is

N2 + 3H2 --> 2 NH3

Thus, 3 moles of hydrogen produces 2 moles of NH3

Hence, the volume of ammonia produced = 5.53 * (2/3) = 3.6867 mL

Hence, 5.53 mL of hydrogen will produce 3.6867 mL of Ammonia

User Aki Nishanov
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