Question

By how many newtons does the weight of a 85.9-kg person lose when he goes from sea level to an altitude of 6.33 km if we neglect the earth's rotational effects

Answer 1

`Weight\ loss=1.6321N`

Step-by-step explanation:

From the question we are told that:

Weight
`W=85.9kg`

Altitude
`h= 6.33 km`

Let

Radius of Earth
`r=6380km`

Gravity
`g=9.8m/s^2`

Generally the equation for Gravity at altitude is mathematically given by

`g_s=9.8((6380)/(6380+6.33))^2`

`g_s=9.781m/s^2`

Therefore

Weight at sea level

`W_s=9.8*85.9`

`W_s=841.82N`

Weight at 6.33 altitude

`W_a=9.781*85.9`

`W_a=840.2N`

Therefore

`Weight loss=W_s-W_b`

`Weight loss=841.82-840.2`

`Weight loss=1.6321N`