Question

50 POINTS

Show work for both questions.

Pleaseee don’t answer if you don’t know, I need this really soon.

Answer 1

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Answer 2

Explanation:

a)

`\sin^(2)x + \cos^(2)x = 1`

Dividing both sides by sin^2x, we get

`1 + (\cos^(2)x )/( \sin^(2)x) = (1)/(\sin^(2)x )`

The 2nd term on the LHS is simply cot^2x and the RHS is simply csc^2x

`1 + \cot^(2)x = \csc^(2)x`

b)

`2 \sin x = 1`

`\sin x = (1)/(2)`

`x = \sin^( - 1) ((1)/(2)) = (\pi)/(6)`

You can also graph it to arrive at the solution.