Question isn't well formatted :
on a restaurant menu you can have three course meal by selecting one from each meal course they're five appetizers four main dishes and two desserts to choose from how many Possible full meals are there?
Answer:
40
Explanation:
To solve questions of this nature, we apply combination.
nCr = n! ÷ (n - r)!r!
For the 3 course meal :
Selection procedure ;
Select 1 appetizer from 5 ; and 1 main dish from four and 1 dessert from 2
This gives :
5C1 * 4C1 * 2C1
5C1 = 5! ÷ (5-1)!1! = 5
4C1 = 4! ÷ (4-1)!1! = 4
2C1 = 2! ÷ (2-1)!1! = 2
Hence, we have
5 * 4 * 2 = 40 different meals