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Find the first term in a geometric sequence in which the common ratio is 5/2 and the tenth is 625/16

Find the first term in a geometric sequence in which the common ratio is 5/2 and the tenth is 625/16
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Find the first term in a geometric sequence in which the common ratio is 5/2 and the tenth is 625/16

User Zazvorniki
by
8.3k points

1 Answer

3 votes

Explanation:


r = (5)/(2) \\ a {r}^(9) = (625)/(15) \\ (1953125a)/(512) = (625)/(15) \\ this \: question \: has \: a \: problem

User Clay Hinson
by
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