Find the first term in a geometric sequence in which the common ratio is 5/2 and the tenth is 625/16

asked Jun 17, 2022 117k views

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3 votes

Explanation:

$r = (5)/(2) \\ a {r}^(9) = (625)/(15) \\ (1953125a)/(512) = (625)/(15) \\ this \: question \: has \: a \: problem$

Clay Hinson answered Jun 23, 2022

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