Question

HELP PLEASE 30 POINTS

2x-3y=8 x-3y=8. solve with linear composition

Answer 1

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The given equations are :

• 
  `2x - 3y = 8`

• 
  `x - 3y = 8`

now, let's substract second equation from first equation :

• 
  `2x - 3y - (x - 3y) = 8 - 8`

• 
  `2x - 3y - x + 3y = 0`

• 
  `x = 0`

now, plug value of x as 0 in the second equation to find value of y :

• 
  `x - 3y = 8`

• 
  `0 - 3y = 8`

• 
  `- 3y = 8`

• 
  `y = - (8)/(3)`

So, the solution of given pair of linear equations is :

• 
  `\boxed{ \boxed{0, - (8)/(3) }}`

Answer 2

(0,-8/3)

Explanation:

2x-3y=8

x-3y=8

Multiply the second equation by -1 and add together

2x-3y=8

-x+3y=-8

---------------------

x +0y =0

x=0

Now we can find y

2x -3y =8

0-3y =8

Divide by -3

-3y/-3 = 8/-3

y = -8/3

(0,-8/3)