Question

A TPpolymer sample with the same cross-sectional areaas the PEtested,but with a 50-mm long gage length is tensile tested. When a tensile load of 1032 N is on the sample, the gage length extends by 0.625 mm. The sample can sustain a load of 2063 N just before permanent deformation begins. Calculate the polymer’s elastic modulus (E) in GPa and its yield strength(Y) in MPa. Show your work.

Answer 1

a) 0.033024 GPa

b) 482.6 MPa

Step-by-step explanation:

Gauge length = 50 mm

Tensile load = 1032 N

extension of gauge length = 0.625 mm

Extent of load sustainable by sample = 2063 N

Assuming a cross section area = 2500 mm^2 = 0.0025 m^2

a) Determine the Elastic modulus of the Polymer

Elastic modulus = stress / strain -------- ( 1 )

= ( f/A / strain )

f/A = force / area = 1032 / 0.0025 m^2 = 4.128 * 10^5 N/m^2

strain = Δl / original l = 0.625 / 50 = 0.0125

Back to equation 1 = 4.128 * 10^5 / 0.0125 = 3.3024 * 10^7 N/m^2

= 0.033024 GPa

b) determine yield strength of Polymer

бy = 482.6 MPa

attached below is the detailed solution