Answer:

Explanation:
we would like to solve the following trigonometric equation on interval of [0,2π)

remember that,

so the equation has two solutions

take inverse trig both sides which yields:

simplify the second equation:

add period of 2kπ:

By making theta subject of the equation we acquire:

since
we get:

as we want to Solve the trigonometric equation on the interval of [0,2π) we get

by simplifying we acquire:

and we are done!
hence,
