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Solve the problem. An experiment consists of randomly choosing a number between 1 and 10. Let E be the event that the number chosen is even. Assuming that each of the numbers between 1 and 10 is equally likely to be chosen, find P(E).

A) .5
B) .8
C) .1
D) .2

User Zan RAKOTO
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Answer:

A.

Explanation:

1. the required probablilty is: P=(number_of_even_numbers)/(number_of_all_the_numbers);

2. according the condition the number of all the numbers is 10; the number of even numbers is 5 (they are: 2; 4; 6; 8; 10), then

3. P=5/10=0.5 (option 'A').

User Brian Rothstein
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