Answer:





Explanation:
Given
Success
Failure
Consecutive trials until S happens
Number of trials
For every possible outcome, the last 3 must be SSS. So, we have:
The only possibility here is:

because 3 trials implies that all outcomes must be S.

The only possibility here is:
because 4 trials implies that the first outcome must be F

The possibilities are:
because 5 trials implies that the first and the second outcomes must be FS or SF.

The possibilities are:
because 6 trials implies that the first three outcomes are: FFF, SSF and SFF
The possibilities are:
because 7 trials implies that the first three outcomes are: FFFF, FSSF and SSFF and FFSF (similar to (e))