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Each time a component is tested the trial is a success (S) or failure (F). Suppose the component is tested repeatedly until a success occurs on three consecutive trials. Let Y denote the number of trials necessary to achieve this. List all outcomes corresponding to the five smallest possile values of Y, and state which Y value is associated with each one.

Y Outcomes
3
4
5
6
7

User Franz See
by
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1 Answer

5 votes

Answer:


(a)\ \{SSS\}


(b)\ \{FSSS\}


(c)\ \{FFSSS, SFSSS\}


(d)\ \{FFFSSS, SSFSSS, SFFSSS, FSFSSS\}


(e)\ \{FFFFSSS, FFSFSSS, FSSFSSS, SSFFSSS, SFSFSSS, SFFFSSS, FSFFSSS\}

Explanation:

Given


S\to Success


F\to Failure


n \to 3 Consecutive trials until S happens


Y \to Number of trials

For every possible outcome, the last 3 must be SSS. So, we have:


(a)\ Y = 3

The only possibility here is:
\{SSS\}

because 3 trials implies that all outcomes must be S.


(b)\ Y = 4

The only possibility here is:


\{FSSS\}

because 4 trials implies that the first outcome must be F


(c)\ Y = 5

The possibilities are:


\{FFSSS, SFSSS\}

because 5 trials implies that the first and the second outcomes must be FS or SF.


(d)\ Y = 6

The possibilities are:


\{FFFSSS, SSFSSS, SFFSSS, FSFSSS\}

because 6 trials implies that the first three outcomes are: FFF, SSF and SFF


(e)\ Y = 7

The possibilities are:


\{FFFFSSS, FFSFSSS, FSSFSSS, SSFFSSS, SFSFSSS, SFFFSSS, FSFFSSS\}

because 7 trials implies that the first three outcomes are: FFFF, FSSF and SSFF and FFSF (similar to (e))

User Jakub Svec
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