Question

Between 06 00 and 10 00,the same day ,the volume of water in a reservoir decreased from 24 000L to 18 000L.What was the average rate of decrease in volume of water, giving your answer in L/h?

Answer 1

-1.5 L/h

Explanation:

The volume of water in a reservoir decreased from 24.000L to 18.000L between 06.00 and 10.00.

We need to find the average rate of decrease in volume of water. It can be solved as follows :

`Rate=(18-24)/(10-6)\\\\=-1.5\ L/h`

The negative sign shows the decrease in volume. Hence, the rate of decrease in volume of water is 1.5 L/h.