Question

Find the horizontal range of a projectile launched at 15 degrees to the horizontal with speed of 40m/s​

Answer 1

To Find :

The horizontal range of a projectile launched at 15 degrees to the horizontal with speed of 40 m/s​.

Solution :

The horizontal range of a projectile is given by :

`R = (u^2 sin 2\theta)/(g)` ( Here, g is acceleration due to gravity = 10 m/s² )

Putting all value in above equation :

`R = (40^2 * sin (2 * 15))/(10) \ m\\\\R = (1600 * 1)/(2* 10) \ m\\\\R = 80 \ m`

Therefore, the horizontal range of projectile is 80 m.