Find the horizontal range of a projectile launched at 15 degrees to the horizontal with speed of 40m/s

Question

asked May 13, 2022 131k views

1 Answer

Gabriel Avellaneda · Answer 1 · 2022-05-18T01:57:45+0000

To Find :

The horizontal range of a projectile launched at 15 degrees to the horizontal with speed of 40 m/s.

Solution :

The horizontal range of a projectile is given by :

$R = (u^2 sin 2\theta)/(g)$ ( Here, g is acceleration due to gravity = 10 m/s² )

Putting all value in above equation :

$R = (40^2 * sin (2 * 15))/(10) \ m\\\\R = (1600 * 1)/(2* 10) \ m\\\\R = 80 \ m$

Therefore, the horizontal range of projectile is 80 m.