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The first 4 terms of the sequence defined by the rule f(n) = 4n^2 + 4

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Answer:


f(n) = 4n^2 + 4

f(1) = 4 x 1 + 4 = 4 + 4 = 8

f(2) = 4 x 4 + 4 = 16 + 4 = 20

f(3) = 4 x 9 + 4 = 36 + 4 =40

f(4) = 4 x 16 + 4 = 64 + 4 = 68

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