Answer:
• The amount of heat required to melt ice and raise the temperature of water T^oCToC is
Q=mL_f+mc\Delta TQ=mLf+mcΔT
Here m=1.5 kgm=1.5kg
L_f=3.33*10^5 J/kgLf=3.33∗105J/kg is Latent heat of fusion of ice.
c=4186 J/kg.^oCc=4186J/kg.oC is heat capacity of water.
\Delta T=50 ^oC-0^oC=50^oCΔT=50oC−0oC=50oC
So,
Q=(1.50)[3.33*10^5 +(4186)(50)]=8.13*10^5 JQ=(1.50)[3.33∗105+(4186)(50)]=8.13∗105J