Question

Maintaining constant pressure, the volume of a gas is increased from 12,0 L

to 32.0 L by heating it. If the original temperature was 23.0°C, what is the
new temperature? *
23. 45 K
61.33 K
789.33 K
567.87 K

Answer 1

790 K

Step-by-step explanation:

Step 1: Given data

• Initial volume of the gas (V₁): 12.0 L

• Initial temperature of the gas (T₁): 23.0 °C

• Final volume of the gas (V₂): 32.0 L

Step 2: Convert 23.0 °C to Kelvin

We will use the following expression.

K = °C + 273.15 = 23.0 + 273.15 = 296.2 K

Step 3: Calculate the final temperature of the gas

Assuming constant pressure and ideal behavior, we can calculate the final temperature of the gas using Charles' law.

T₁/V₁ = T₂/V₂

T₂ = T₁ × V₂/V₁

T₂ = 296.2 K × 32.0 L/12.0 L = 790 K