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Solve for (0,2π]
2cos ß * sin ß = cos ß

1 Answer

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Given :

An equation, 2cos ß sin ß = cos ß .

To Find :

The value for above equation in (0, 2π ] .

Solution :

Now, 2cos ß sin ß = cos ß

2 sin ß = 1

sin ß = 1/2

We know, sin ß = sin (π/6) or sin ß = sin (5π/6) in ( 0, 2π ] .

Therefore,


\beta = (\pi)/(6)\ or\ \beta = (5\pi)/(6)

Hence, this is the required solution.

User Tuespetre
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