Given :
An equation, 2cos ß sin ß = cos ß .
To Find :
The value for above equation in (0, 2π ] .
Solution :
Now, 2cos ß sin ß = cos ß
2 sin ß = 1
sin ß = 1/2
We know, sin ß = sin (π/6) or sin ß = sin (5π/6) in ( 0, 2π ] .
Therefore,
![\beta = (\pi)/(6)\ or\ \beta = (5\pi)/(6)](https://img.qammunity.org/2022/formulas/mathematics/college/g75sub07w53fnnrfwzr7z2h212hkdut8km.png)
Hence, this is the required solution.