Question

Find the sum of the geometric series 1 - 4/5 + (4/5)² - (4/5)³ + ... - (4/5)²⁹

Answer 1

Explanation:

Given,

1st term (a) = 1

Common ratio (r) = -4/5

last term (l) = -
`(4/5)^(29)`

Now,

Sum (S) = (lr- a)/(r - 1) =[(4/5)³° - 1]/(-9/5)

= -0.99876206/-1.8

= 0.5548678111

Sorry bro couldn't get answer in fraction.