Explanation:
First, set the equations as equal to eachother because both equal y:

Now, solve to get everything on one side of the equation so that the other side of the equation is set to 0:

Now use the sum product pattern:

(as you can see, the above equation is equivalent to the previous equation, but there are now four values instead of three)
Now take the common factor from the two pairs:

Rewrite in factored form:

Now to get both values of x, set each factored equation to 0 and solve for x (becuase remember, the equation still equals 0):


NOW that we have both values of x, we can subsitute them into EITHER equation and solve to get the corresponding y values:


So that's how we solve to get these coordinates: (8,9) & (-1,0).
Good luck on your final and I hope I was able to help :)