Question

When a light bulb is connected to a 4.5 V battery, a current of 0.16 A passes through the bulb filament. What is the resistance of the filament

Answer 1

R = 28.125 ohms

Step-by-step explanation:

Given that,

The voltage of a bulb, V = 4.5 V

Current, I = 0.16 A

We need to find the resistance of the filament. Using Ohm's law,

V = IR

Where

R is the resistance of the filament

So,

`R=(V)/(I)\\\\R=(4.5)/(0.16)\\\\R=28.125\ \Omega`

So, the resistance of the filament is equal to 28.125 ohms.