Question

1.8 A water flow of 4.5 slug/s at 60 F enters the condenser of steam turbine and leaves at 140 F. Determine the heat transfer rate (Btu/hr)

Answer 1

`Hr=4.2*10^7\ btu/hr`

Step-by-step explanation:

From the question we are told that:

Water flow Rate
`R=4.5slug/s=144.78ib/sec`

Initial Temperature
`T_1=60 \textdegree F`

Final Temperature
`T_2=140 \textdegree F`

Let

Specific heat of water
`\gamma= 1`

And

`\triangle T= 140-60`

`\triangle T= 80\ Deg.F`

Generally the equation for Heat transfer rate of water
`H_r` is mathematically given by

Heat transfer rate to water= mass flow rate* specific heat* change in temperature

`H_r=R* \gamma*\triangle T`

`H_r=144.78*80*1`

`H_r=11582.4\ btu/sec`

Therefore

`H_r=11582.4\ btu/sec*3600`

`Hr=4.2*10^7\ btu/hr`