Answer: The pressure in the tires at that point is 528.52 kPa.
Step-by-step explanation:
Given:
= 500 K,
= 500 kPa
= 315 K,
= ?
According to Gay-Lussac's law, at constant volume the pressure of a gas is directly proportional to temperature.
Formula used to calculate the pressure is as follows.
![(P_(1))/(T_(1)) = (P_(2))/(T_(2))](https://img.qammunity.org/2022/formulas/chemistry/high-school/xgzg9ki5fjrv6su2gs6n8r83l3uyspoqn9.png)
Substitute the values into above formula as follows.
![(P_(1))/(T_(1)) = (P_(2))/(T_(2))\\(500 kPa)/(298 K) = (P_(2))/(315 K)\\P_(2) = 528.52 kPa](https://img.qammunity.org/2022/formulas/chemistry/college/81krmyieehby6nglgwgbbwjbkksqpoopi1.png)
Thus, we can conclude that the pressure in the tires at that point is 528.52 kPa.