Question

The function f(x) is a quadratic function and the zeros of f(x) are 3 and 4. Assume

the leading coefficient of f(x) is 1. Write the equation of the quadratic polynomial in
standard form.

Answer 1

y=x²-7x+12

Explanation:

Since the zeroes are 3 and 4, those are also the x-intercepts. That means that the two factors would be (x-3) and (x-4).

Basic factored form is y=a(x-zero) (x-zero). In your case, it would start as:

y=1(x-3)(x-4)

Standard form is when it's multiplied out and in the form:

y=ax²+bx+c. so you need to multiply the factored form or completely.