Answer:
For a data set of N elements:
{x₁, x₂, ..., xₙ}
The median is the middle value (or the average of the two middle values)
The average or mean is:
![m = (x_1 + ... + x_n)/(N)](https://img.qammunity.org/2022/formulas/mathematics/college/5v47tkxqwsnbqgntdp3x9yel1pskyhwo2m.png)
The mode is the value that is more repeated.
The range is the difference between the largest value and the smallest value.
Now, let's try to construct two sets A and B that meet the required conditions:
Let's suppose two sets of 5 values each:
A = {2, 2, 3, 4, 5}
The median of A is 3.
The range of A is = 5 - 2 = 3
The average of A is: (2 + 2 +3 +4 +5)/5 = 16/5
And the value "2" appears two times, so the mode is 2.
Now, let's try to find a data set B such that:
The mode is smaller than 2 (so for example, we can have a "1" that repeats two times)
The median is smaller than 3 (let's have a median equal to 2)
The average is larger than 16/5
The range is larger than 3
This is ratter simple:
B = {1, 1, 2, 6, 9}
The median of B is 2.
The mode of B is 1
The range of B is: 9 - 1 = 8
The average of B is: (1 + 1 + 2 + 6 + 9)/5 = 19/5
So, we just found an example for two data sets A and B such that A has a greater median and mode, while B has a greater average and range.
So the answer is yes, it is possible.