Twice once number added to another number is 18. If the second number is equal to 12 less than 4 times the first number, find the first two numbers. 2x+y= 12 ; y= __x - __ I really need help with the second

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asked Jun 4, 2022 108k views

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Twice once number added to another number is 18. If the second number is equal to 12 less than 4 times the first number, find the first two numbers.

2x+y= 12 ; y= __x - __

I really need help with the second part...

Mathematics
high-school

Gordie asked

by Gordie

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1 Answer

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Explanation:

2x+y= 12

= 12,18

= 36

so the value of y is 36

value of x is 48

Simon Thiel answered Jun 8, 2022

by Simon Thiel

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