Question

g how many moles of NO are produced if 2.5 mol of O2 react completely with 4.0 mol of NH3 (molar mass of NO

Answer 1

2 moles of NO

Step-by-step explanation:

Our reaction is:

4NH₃ + 5O₂ → 6H₂O + 4NO

4 moles of ammonia react to 5 moles of oxygen in order to produce 6 moles of water and 4 moles of NO

We need to determine the limiting reactant:

Ratio is 4:5, As 4 moles of ammonia react to 5 moles of oxygen and we have 4 moles, we definetely need 5 moles, but the problem is, we only have 2.5 moles of O₂. Oxygen is the limting reagent.

5 moles of O₂ produce 4 moles of NO, according to stoichiometry

2.5 moles of O₂ may produce (2.5 . 4) / 5 = 2 moles of NO